What is the answer to log_{2}(z+6)=log_{2}(z-1)+3 ?

The answer to log_{2}(z+6)=log_{2}(z-1)+3 is z=2

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log_{2}(z+6)=log_{2}(z-1)+3

lo g_{2} (z + 6) = lo g_{2} (z - 1) + 3

z = 2

Solution steps

lo g_{2} (z + 6) = lo g_{2} (z - 1) + 3

Apply log rules

z + 6 = (z - 1) \cdot 8

Solve

z + 6 = (z - 1) \cdot 8 : z = 2

z = 2

Verify Solutions:

z = 2

True

The solution is

z = 2

0.5075 = - lo g_{10} (x)

lo g_{3} (x - 5) = - 2

- 1 = ln (7 x)

ln (x^{2}) - ln (5) = 4

lo g_{2} (x^{2}) = 3

What is the answer to log_{2}(z+6)=log_{2}(z-1)+3 ?
The answer to log_{2}(z+6)=log_{2}(z-1)+3 is z=2
Solve for z: log_{2}(z+6)=log_{2}(z-1)+3
The solution is z=2