What is the answer to 400=300log_{10}(d)+65 ?

The answer to 400=300log_{10}(d)+65 is d=10*10^{7/60}

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400=300log_{10}(d)+65

400 = 300 lo g_{10} (d) + 65

d = 10 \cdot 1 0^{\frac{7}{60}}

Solution steps

400 = 300 lo g_{10} (d) + 65

Switch sides

300 lo g_{10} (d) + 65 = 400

Move

65

to the right side

300 lo g_{10} (d) = 335

Divide both sides by

300

lo g_{10} (d) = \frac{67}{60}

Apply log rules

d = 10 \cdot 1 0^{\frac{7}{60}}

Verify Solutions:

d = 10 \cdot 1 0^{\frac{7}{60}}

True

The solution is

d = 10 \cdot 1 0^{\frac{7}{60}}

lo g_{3} (2 + x) - lo g_{3} (2 - x) = 3

lo g_{3} (x + 7) - lo g_{3} (x - 7) = 2

y, x = ln (2 y - 1)

3 lo g_{8} (2 x + 7) + 8 = 10

lo g_{4} (x - 3) + lo g_{4} (4 x + 3) = 1

What is the answer to 400=300log_{10}(d)+65 ?
The answer to 400=300log_{10}(d)+65 is d=10*10^{7/60}
Solve for d: 400=300log_{10}(d)+65
The solution is d=10*10^{7/60}