What is the answer to 3log_{8}(2x+7)+8=10 ?

The answer to 3log_{8}(2x+7)+8=10 is x=-3/2

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3log_{8}(2x+7)+8=10

3 lo g_{8} (2 x + 7) + 8 = 10

x = - \frac{3}{2}

Solution steps

3 lo g_{8} (2 x + 7) + 8 = 10

Move

8

to the right side

3 lo g_{8} (2 x + 7) = 2

Divide both sides by

3

lo g_{8} (2 x + 7) = \frac{2}{3}

Apply log rules

2 x + 7 = 4

Solve

2 x + 7 = 4 : x = - \frac{3}{2}

x = - \frac{3}{2}

Verify Solutions:

x = - \frac{3}{2}

True

The solution is

x = - \frac{3}{2}

lo g_{4} (x - 3) + lo g_{4} (4 x + 3) = 1

lo g_{x} (2) = 128

x ln (x) - x = 0

- 1 - ln (2 + x) = 0

ln (\frac{1}{x}) = - ln (x)

What is the answer to 3log_{8}(2x+7)+8=10 ?
The answer to 3log_{8}(2x+7)+8=10 is x=-3/2
Solve for x: 3log_{8}(2x+7)+8=10
The solution is x=-3/2