What is the answer to (x+n)/(2ln(x)-n)=0 ?

The answer to (x+n)/(2ln(x)-n)=0 is x=-n {n<-2\W_{0}(1/2)\lor-2\W_{0}(1/2)<n<0}

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(x+n)/(2ln(x)-n)=0

\frac{x + n}{2 ln ( x ) - n} = 0

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}

Solution steps

\frac{x + n}{2 ln ( x ) - n} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x + n = 0

Move

x

to the right side

n = - x

Solve

n = - x : x = - n

x = - n

Verify Solutions:

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}

The solution is

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}

lo g_{3} (9 x) + lo g_{3} (8) = 5

lo g_{6} (x + 7) + lo g_{6} (x + 4) = 2

50 = - 22.985 ln (x) + 139.23

lo g_{1000} (a) = \frac{1}{3}

y, ln (y - 47) = 6 t

What is the answer to (x+n)/(2ln(x)-n)=0 ?
The answer to (x+n)/(2ln(x)-n)=0 is x=-n {n<-2\W_{0}(1/2)\lor-2\W_{0}(1/2)<n<0}