What is the answer to log_{b}(x^2-2)=log_{b}(x) ?

The answer to log_{b}(x^2-2)=log_{b}(x) is x=2 {0 1}

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log_{b}(x^2-2)=log_{b}(x)

lo g_{b} (x^{2} - 2) = lo g_{b} (x)

x = 2 {0 < b < 1 or b > 1}

Solution steps

lo g_{b} (x^{2} - 2) = lo g_{b} (x)

Apply log rules

x^{2} - 2 = x

Solve

x^{2} - 2 = x : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2 {0 < b < 1 or b > 1}, x = - 1

False

The solution is

x = 2 {0 < b < 1 or b > 1}

ln (x - 3) = 5

lo g_{\frac{1}{3}} (x) = 243

(lo g_{2} (x))^{2} - 1 = 0

2 lo g_{p} (9) + 3 lo g_{3} (p) = 8

\frac{n}{lo g _{2} ( n )} = 8

What is the answer to log_{b}(x^2-2)=log_{b}(x) ?
The answer to log_{b}(x^2-2)=log_{b}(x) is x=2 {0<b<1\lor b>1}