What is the answer to (log_{2}(x))^2-1=0 ?

The answer to (log_{2}(x))^2-1=0 is x=2,x= 1/2

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(log_{2}(x))^2-1=0

(lo g_{2} (x))^{2} - 1 = 0

x = 2, x = \frac{1}{2}

Solution steps

(lo g_{2} (x))^{2} - 1 = 0

Rewrite the equation with

lo g_{2} (x) = u

(u)^{2} - 1 = 0

Solve

u^{2} - 1 = 0 : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = lo g_{2} (x),

solve for

x

Solve

lo g_{2} (x) = 1 : x = 2

Solve

lo g_{2} (x) = - 1 : x = \frac{1}{2}

x = 2, x = \frac{1}{2}

Verify Solutions:

x = 2

True

, x = \frac{1}{2}

True

The solutions are

x = 2, x = \frac{1}{2}

2 lo g_{p} (9) + 3 lo g_{3} (p) = 8

\frac{n}{lo g _{2} ( n )} = 8

2 lo g_{6} (x - 7) + lo g_{6} (9) = 2

lo g_{8} (x) = 0.333

2 lo g_{3} (x) - lo g_{27} (x) = 10

What is the answer to (log_{2}(x))^2-1=0 ?
The answer to (log_{2}(x))^2-1=0 is x=2,x= 1/2
Solve for x: (log_{2}(x))^2-1=0
The solution is x=2,x= 1/2