What is the answer to log_{10}((x+2)(x-1))=1 ?

The answer to log_{10}((x+2)(x-1))=1 is x=3,x=-4

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log_{10}((x+2)(x-1))=1

lo g_{10} ((x + 2) (x - 1)) = 1

x = 3, x = - 4

Solution steps

lo g_{10} ((x + 2) (x - 1)) = 1

Apply log rules

(x + 2) (x - 1) = 10

Solve

(x + 2) (x - 1) = 10 : x = 3, x = - 4

x = 3, x = - 4

1.73 = - lo g_{10} (x)

10 0^{l o g_{10} (x)} = 2 x^{2}

x^{l o g_{10} (x^{2}) + 1} = x^{3}

lo g_{6} (x) - lo g_{6} (x - 1) = 2

lo g_{2} (x + 4) = 0

What is the answer to log_{10}((x+2)(x-1))=1 ?
The answer to log_{10}((x+2)(x-1))=1 is x=3,x=-4
Solve for x: log_{10}((x+2)(x-1))=1
The solution is x=3,x=-4