What is the answer to log_{12}(4x-2)=0 ?

The answer to log_{12}(4x-2)=0 is x= 3/4

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log_{12}(4x-2)=0

lo g_{12} (4 x - 2) = 0

x = \frac{3}{4}

Solution steps

lo g_{12} (4 x - 2) = 0

Apply log rules

4 x - 2 = 1

Solve

4 x - 2 = 1 : x = \frac{3}{4}

x = \frac{3}{4}

lo g_{3} (x^{2} - 2 x + 3) = 1

ln (\frac{1}{x}) = 4

lo g_{10} (x) = 0.58

lo g_{10} (x) 4 = 2

50 = 10 \cdot lo g_{10} (x)

What is the answer to log_{12}(4x-2)=0 ?
The answer to log_{12}(4x-2)=0 is x= 3/4
Solve for x: log_{12}(4x-2)=0
The solution is x= 3/4