What is the answer to solvefor x,ln(y)=2ln(x)+2c ?

The answer to solvefor x,ln(y)=2ln(x)+2c is x=e^{(ln(y)-2c)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(y)=2ln(x)+2c

solve for

x, ln (y) = 2 ln (x) + 2 c

x = e^{\frac{l n ( y ) - 2 c}{2}}

Solution steps

ln (y) = 2 ln (x) + 2 c

Switch sides

2 ln (x) + 2 c = ln (y)

Move

2 c

to the right side

2 ln (x) = ln (y) - 2 c

Divide both sides by

2

ln (x) = \frac{ln ( y ) - 2 c}{2}

Apply log rules

x = e^{\frac{l n ( y ) - 2 c}{2}}

lo g_{2 - x} (2 x^{2} - 1) = 2

lo g_{e} (x - 2) - 3 lo g_{e} (2) = 2

ln (x + 5) - ln (x - 4) = ln (x)

2 lo g_{10} (x) = lo g_{10} (x) + 3

ln (x) + ln (x + 1) = 2

What is the answer to solvefor x,ln(y)=2ln(x)+2c ?
The answer to solvefor x,ln(y)=2ln(x)+2c is x=e^{(ln(y)-2c)/2}