What is the answer to log_{4}(x+3)-log_{4}(x-3)=2 ?

The answer to log_{4}(x+3)-log_{4}(x-3)=2 is x= 17/5

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log_{4}(x+3)-log_{4}(x-3)=2

lo g_{4} (x + 3) - lo g_{4} (x - 3) = 2

x = \frac{17}{5}

Solution steps

lo g_{4} (x + 3) - lo g_{4} (x - 3) = 2

Add

lo g_{4} (x - 3)

to both sides

lo g_{4} (x + 3) - lo g_{4} (x - 3) + lo g_{4} (x - 3) = 2 + lo g_{4} (x - 3)

Simplify

lo g_{4} (x + 3) = 2 + lo g_{4} (x - 3)

Apply log rules

x + 3 = 16 (x - 3)

Solve

x + 3 = 16 (x - 3) : x = \frac{17}{5}

x = \frac{17}{5}

Verify Solutions:

x = \frac{17}{5}

True

The solution is

x = \frac{17}{5}

lo g_{10} (\frac{L}{15}) = 1

lo g_{10} (8) - lo g_{10} (x) = 1

x, ln (x + 7) + ln (x - 7) = 0

7 = 3 lo g_{10} (8 t + 10)

ln (e - x + 7 + 3) = 50

What is the answer to log_{4}(x+3)-log_{4}(x-3)=2 ?
The answer to log_{4}(x+3)-log_{4}(x-3)=2 is x= 17/5
Solve for x: log_{4}(x+3)-log_{4}(x-3)=2
The solution is x= 17/5