What is the answer to log_{10}(8)-log_{10}(x)=1 ?

The answer to log_{10}(8)-log_{10}(x)=1 is x= 4/5

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log_{10}(8)-log_{10}(x)=1

lo g_{10} (8) - lo g_{10} (x) = 1

x = \frac{4}{5}

Solution steps

lo g_{10} (8) - lo g_{10} (x) = 1

Move

lo g_{10} (8)

to the right side

- lo g_{10} (x) = 1 - lo g_{10} (8)

Divide both sides by

- 1

lo g_{10} (x) = - 1 + lo g_{10} (8)

Apply log rules

x = \frac{4}{5}

Verify Solutions:

x = \frac{4}{5}

True

The solution is

x = \frac{4}{5}

x, ln (x + 7) + ln (x - 7) = 0

7 = 3 lo g_{10} (8 t + 10)

ln (e - x + 7 + 3) = 50

x, lo g_{4} (x + y) = 3

ln (x) + ln (2 x - 1) = 0

What is the answer to log_{10}(8)-log_{10}(x)=1 ?
The answer to log_{10}(8)-log_{10}(x)=1 is x= 4/5
Solve for x: log_{10}(8)-log_{10}(x)=1
The solution is x= 4/5