What is the answer to solvefor x,5+log_{2}(-5x)=9 ?

The answer to solvefor x,5+log_{2}(-5x)=9 is x=-16/5

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solvefor x,5+log_{2}(-5x)=9

solve for

x, 5 + lo g_{2} (- 5 x) = 9

x = - \frac{16}{5}

Solution steps

5 + lo g_{2} (- 5 x) = 9

Move

5

to the right side

lo g_{2} (- 5 x) = 4

Apply log rules

- 5 x = 16

Solve

- 5 x = 16 : x = - \frac{16}{5}

x = - \frac{16}{5}

Verify Solutions:

x = - \frac{16}{5}

True

The solution is

x = - \frac{16}{5}

3 + lo g_{8} (- 5 n) = 6

lo g_{10} (x) = - 8.746

lo g_{7} ((3 x - 8)^{3}) = 6

ln (3 x - 18) = 9

lo g_{10} (x) + lo g_{10} (3 - x) = 0

What is the answer to solvefor x,5+log_{2}(-5x)=9 ?
The answer to solvefor x,5+log_{2}(-5x)=9 is x=-16/5