What is the answer to log_{10}(x)+log_{10}(3-x)=0 ?

The answer to log_{10}(x)+log_{10}(3-x)=0 is x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2

Solve for x: log_{10}(x)+log_{10}(3-x)=0

The solution is x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2

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lo g_{10} (x) + lo g_{10} (3 - x) = 0

x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

Solution steps

lo g_{10} (x) + lo g_{10} (3 - x) = 0

Apply log rules

x (3 - x) = 1

Solve

x (3 - x) = 1 : x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

Verify Solutions:

x = \frac{3 - 5}{2}

True

, x = \frac{3 + 5}{2}

True

The solutions are

x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

x, ln (3 x - 15) = 5

ln (3 x - 18) = 6

ln (3 x - 18) = 5

lo g_{2} ((x + 1) (x - 1)) = 3

lo g_{x} (3) = - \frac{1}{2}

What is the answer to log_{10}(x)+log_{10}(3-x)=0 ?
The answer to log_{10}(x)+log_{10}(3-x)=0 is x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2
Solve for x: log_{10}(x)+log_{10}(3-x)=0
The solution is x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2