What is the answer to log_{2}((x+1)(x-1))=3 ?

The answer to log_{2}((x+1)(x-1))=3 is x=3,x=-3

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log_{2}((x+1)(x-1))=3

lo g_{2} ((x + 1) (x - 1)) = 3

x = 3, x = - 3

Solution steps

lo g_{2} ((x + 1) (x - 1)) = 3

Apply log rules

(x + 1) (x - 1) = 8

Solve

(x + 1) (x - 1) = 8 : x = 3, x = - 3

x = 3, x = - 3

lo g_{x} (3) = - \frac{1}{2}

0.4 = lo g_{10} (y)

lo g_{4} (x) - lo g_{4} (2 x - 1) = 1

75 = 20 lo g_{10} (\frac{800}{x})

lo g_{2} (8 x + 5) = 5

What is the answer to log_{2}((x+1)(x-1))=3 ?
The answer to log_{2}((x+1)(x-1))=3 is x=3,x=-3
Solve for x: log_{2}((x+1)(x-1))=3
The solution is x=3,x=-3