What is the answer to log_{2}(8x+5)=5 ?

The answer to log_{2}(8x+5)=5 is x= 27/8

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log_{2}(8x+5)=5

lo g_{2} (8 x + 5) = 5

x = \frac{27}{8}

Solution steps

lo g_{2} (8 x + 5) = 5

Apply log rules

8 x + 5 = 32

Solve

8 x + 5 = 32 : x = \frac{27}{8}

x = \frac{27}{8}

6 + 7 \cdot lo g_{2} (x) = 21

lo g_{3} (2 x - 3) + lo g_{3} (x + 3) = 4

lo g_{2} (x + 6) = 2 + lo g_{2} (x + 3)

lo g_{4} (x + 9) = 2

17 = 10 lo g_{a} (x)

What is the answer to log_{2}(8x+5)=5 ?
The answer to log_{2}(8x+5)=5 is x= 27/8
Solve for x: log_{2}(8x+5)=5
The solution is x= 27/8