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Popular >

17=10log_{a}(x)

Solution

17 = 10 lo g_{a} (x)

Solution

x = a^{\frac{17}{10}} {0 < a < 1 or a > 1}

Solution steps

17 = 10 lo g_{a} (x)

Switch sides

10 lo g_{a} (x) = 17

Divide both sides by

10

lo g_{a} (x) = \frac{17}{10}

Apply log rules

x = a^{\frac{17}{10}}

Verify Solutions:

x = a^{\frac{17}{10}} {0 < a < 1 or a > 1}

The solution is

x = a^{\frac{17}{10}} {0 < a < 1 or a > 1}

Popular Examples

log_{4}(x)= 25/10

lo g_{4} (x) = \frac{25}{10}

2ln(x+4)-ln(x)=ln(x+a)

2 ln (x + 4) - ln (x) = ln (x + a)

ln(3.5x+1.1)-1.2=16.7

ln (3.5 x + 1.1) - 1.2 = 16.7

ln(10ln(x))=ln(5)

ln (10 ln (x)) = ln (5)

5 ln (x) = 35

Frequently Asked Questions (FAQ)

What is the answer to 17=10log_{a}(x) ?
The answer to 17=10log_{a}(x) is x=a^{17/10} {0<a<1\lor a>1}