What is the answer to ln(3.5x+1.1)-1.2=16.7 ?

The answer to ln(3.5x+1.1)-1.2=16.7 is x=(e^{17.9}-1.1)/(3.5)

Solve for x: ln(3.5x+1.1)-1.2=16.7

The solution is x=(e^{17.9}-1.1)/(3.5)

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ln (3.5 x + 1.1) - 1.2 = 16.7

x = \frac{e ^{17.9} - 1.1}{3.5}

Solution steps

ln (3.5 x + 1.1) - 1.2 = 16.7

Move

1.2

to the right side

ln (3.5 x + 1.1) = 17.9

Apply log rules

3.5 x + 1.1 = e^{17.9}

Solve

3.5 x + 1.1 = e^{17.9} : x = \frac{e ^{17.9} - 1.1}{3.5}

x = \frac{e ^{17.9} - 1.1}{3.5}

Verify Solutions:

x = \frac{e ^{17.9} - 1.1}{3.5}

True

The solution is

x = \frac{e ^{17.9} - 1.1}{3.5}

ln (10 ln (x)) = ln (5)

5 ln (x) = 35

lo g_{3} ((r + 18)^{2}) = 4

lo g_{2} (2 x) - 2 lo g_{2} (x - 1) = 2

lo g_{\frac{3}{2}} (x) = 3

What is the answer to ln(3.5x+1.1)-1.2=16.7 ?
The answer to ln(3.5x+1.1)-1.2=16.7 is x=(e^{17.9}-1.1)/(3.5)
Solve for x: ln(3.5x+1.1)-1.2=16.7
The solution is x=(e^{17.9}-1.1)/(3.5)