What is the answer to log_{2}(2x)-2log_{2}(x-1)=2 ?

The answer to log_{2}(2x)-2log_{2}(x-1)=2 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(2x)-2log_{2}(x-1)=2

lo g_{2} (2 x) - 2 lo g_{2} (x - 1) = 2

x = 2

Solution steps

lo g_{2} (2 x) - 2 lo g_{2} (x - 1) = 2

Apply log rules

2 x = 4 (x - 1)^{2}

Solve

2 x = 4 (x - 1)^{2} : x = 2, x = \frac{1}{2}

x = 2, x = \frac{1}{2}

Verify Solutions:

x = 2

True

, x = \frac{1}{2}

False

The solution is

x = 2

lo g_{\frac{3}{2}} (x) = 3

2 lo g_{10} (x + 1) = 2 - x

lo g_{6} (x) + lo g_{6} (x + 1) = 1

lo g_{10} (a + 4) = 5.2

lo g_{10} (10 x) = 4

What is the answer to log_{2}(2x)-2log_{2}(x-1)=2 ?
The answer to log_{2}(2x)-2log_{2}(x-1)=2 is x=2
Solve for x: log_{2}(2x)-2log_{2}(x-1)=2
The solution is x=2