What is the answer to log_{6}(x)+log_{6}(x+1)=1 ?

The answer to log_{6}(x)+log_{6}(x+1)=1 is x=2

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log_{6}(x)+log_{6}(x+1)=1

lo g_{6} (x) + lo g_{6} (x + 1) = 1

x = 2

Solution steps

lo g_{6} (x) + lo g_{6} (x + 1) = 1

Apply log rules

x (x + 1) = 6

Solve

x (x + 1) = 6 : x = 2, x = - 3

x = 2, x = - 3

Verify Solutions:

x = 2

True

, x = - 3

False

The solution is

x = 2

lo g_{10} (a + 4) = 5.2

lo g_{10} (10 x) = 4

ln (x^{2} - 1) - ln (x - 1) = 2

2 lo g_{x} (2) = lo g_{2} (x) + 1

lo g_{8} (16) + lo g_{8} (x - 2) = 2

What is the answer to log_{6}(x)+log_{6}(x+1)=1 ?
The answer to log_{6}(x)+log_{6}(x+1)=1 is x=2
Solve for x: log_{6}(x)+log_{6}(x+1)=1
The solution is x=2