What is the answer to log_{6}(x+1)=2-log_{6}(2) ?

The answer to log_{6}(x+1)=2-log_{6}(2) is x=17

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log_{6}(x+1)=2-log_{6}(2)

lo g_{6} (x + 1) = 2 - lo g_{6} (2)

x = 17

Solution steps

lo g_{6} (x + 1) = 2 - lo g_{6} (2)

Apply log rules

x + 1 = 18

Solve

x + 1 = 18 : x = 17

x = 17

2 lo g_{3} (4 x + 1) = 4

ln (x + 2) + \frac{x}{x + 2} = 0

lo g_{2.718} (a) = 9.06

6 k + ln (1 - 4 k) = 0

ln (x) = ln (5) + ln (8)

What is the answer to log_{6}(x+1)=2-log_{6}(2) ?
The answer to log_{6}(x+1)=2-log_{6}(2) is x=17
Solve for x: log_{6}(x+1)=2-log_{6}(2)
The solution is x=17