What is the answer to log_{2}(3-2x)=3 ?

The answer to log_{2}(3-2x)=3 is x=-5/2

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log_{2}(3-2x)=3

lo g_{2} (3 - 2 x) = 3

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

lo g_{2} (3 - 2 x) = 3

Apply log rules

3 - 2 x = 8

Solve

3 - 2 x = 8 : x = - \frac{5}{2}

x = - \frac{5}{2}

ln (x + 1) = 1.86

lo g_{10} (x) + lo g_{10} (2 x) = 5

y ln (x - y) = 0

ln (x) + 6 = 0

ln (x) + 6 = 4