What is the answer to log_{10}(x)+log_{10}(2x)=5 ?

The answer to log_{10}(x)+log_{10}(2x)=5 is x=10^{(5-log_{10}(2))/2}

Solve for x: log_{10}(x)+log_{10}(2x)=5

The solution is x=10^{(5-log_{10}(2))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (x) + lo g_{10} (2 x) = 5

x = 1 0^{\frac{5 - l o g _{10} ( 2 )}{2}}

Decimal Notation

x = 223.60679 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (2 x) = 5

Apply log rules

x = 1 0^{\frac{5 - l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{5 - l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{5 - l o g _{10} ( 2 )}{2}}

y ln (x - y) = 0

ln (x) + 6 = 0

ln (x) + 6 = 4

lo g_{5} (x - 3) + lo g_{5} (x + 21) = 2

ln ((x + 2)^{2}) = 2

What is the answer to log_{10}(x)+log_{10}(2x)=5 ?
The answer to log_{10}(x)+log_{10}(2x)=5 is x=10^{(5-log_{10}(2))/2}
Solve for x: log_{10}(x)+log_{10}(2x)=5
The solution is x=10^{(5-log_{10}(2))/2}