What is the answer to ln((x+2)^2)=2 ?

The answer to ln((x+2)^2)=2 is x=e-2,x=-e-2

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ln((x+2)^2)=2

ln ((x + 2)^{2}) = 2

x = e - 2, x = - e - 2

Decimal Notation

x = 0.71828 \dots, x = - 4.71828 \dots

Solution steps

ln ((x + 2)^{2}) = 2

Apply log rules

(x + 2)^{2} = e^{2}

Solve

(x + 2)^{2} = e^{2} : x = e - 2, x = - e - 2

x = e - 2, x = - e - 2

lo g_{2} (- x^{2} + 2 x) = 0

ln (x + 8) + ln (x - 8) = 0

ln (3 x + 8) = ln (2 x + 2) + ln (x - 2)

lo g_{2} (x + 2) - lo g_{2} (x - 2) = 2

lo g_{3} (x + 7) = 3

What is the answer to ln((x+2)^2)=2 ?
The answer to ln((x+2)^2)=2 is x=e-2,x=-e-2
Solve for x: ln((x+2)^2)=2
The solution is x=e-2,x=-e-2