What is the answer to log_{2}(-x^2+2x)=0 ?

The answer to log_{2}(-x^2+2x)=0 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(-x^2+2x)=0

lo g_{2} (- x^{2} + 2 x) = 0

x = 1

Solution steps

lo g_{2} (- x^{2} + 2 x) = 0

Apply log rules

- x^{2} + 2 x = 1

Solve

- x^{2} + 2 x = 1 : x = 1

x = 1

ln (x + 8) + ln (x - 8) = 0

ln (3 x + 8) = ln (2 x + 2) + ln (x - 2)

lo g_{2} (x + 2) - lo g_{2} (x - 2) = 2

lo g_{3} (x + 7) = 3

1.034 + 1.4758 = 1.0445 ln (x)

What is the answer to log_{2}(-x^2+2x)=0 ?
The answer to log_{2}(-x^2+2x)=0 is x=1
Solve for x: log_{2}(-x^2+2x)=0
The solution is x=1