What is the answer to log_{2}(x+4)+log_{2}(x-2)=4 ?

The answer to log_{2}(x+4)+log_{2}(x-2)=4 is x=4

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log_{2}(x+4)+log_{2}(x-2)=4

lo g_{2} (x + 4) + lo g_{2} (x - 2) = 4

x = 4

Solution steps

lo g_{2} (x + 4) + lo g_{2} (x - 2) = 4

Apply log rules

(x + 4) (x - 2) = 16

Solve

(x + 4) (x - 2) = 16 : x = 4, x = - 6

x = 4, x = - 6

Verify Solutions:

x = 4

True

, x = - 6

False

The solution is

x = 4

ln (7 x + e) = 7

lo g_{x} (x^{2} - 2 x - 1) = 2

ln (x) = 1.2

ln (x) = 1.3

ln (x) = 1.8

What is the answer to log_{2}(x+4)+log_{2}(x-2)=4 ?
The answer to log_{2}(x+4)+log_{2}(x-2)=4 is x=4
Solve for x: log_{2}(x+4)+log_{2}(x-2)=4
The solution is x=4