What is the answer to log_{x}(x^2-2x-1)=2 ?

The answer to log_{x}(x^2-2x-1)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x}(x^2-2x-1)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x} (x^{2} - 2 x - 1) = 2

No Solution for x \in R

Solution steps

lo g_{x} (x^{2} - 2 x - 1) = 2

Apply log rules

\frac{ln ( x ^{2} - 2 x - 1 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( x ^{2} - 2 x - 1 )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (x^{2} - 2 x - 1) = 2 ln (x)

Apply log rules

x^{2} - 2 x - 1 = x^{2}

Solve

x^{2} - 2 x - 1 = x^{2} : x = - \frac{1}{2}

x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

False

The solution is

No Solution for x \in R

ln (x) = 1.2

ln (x) = 1.3

ln (x) = 1.8

(ln (x))^{2} - 3 ln (x) + 2 = 0

lo g_{3} (8 x + 1) - lo g_{3} (x) = 1

What is the answer to log_{x}(x^2-2x-1)=2 ?
The answer to log_{x}(x^2-2x-1)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x}(x^2-2x-1)=2
The solution is No Solution for x\in\mathbb{R}