What is the answer to log_{3}(8x+1)-log_{3}(x)=1 ?

The answer to log_{3}(8x+1)-log_{3}(x)=1 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(8x+1)-log_{3}(x)=1

The solution is No Solution for x\in\mathbb{R}

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lo g_{3} (8 x + 1) - lo g_{3} (x) = 1

No Solution for x \in R

Solution steps

lo g_{3} (8 x + 1) - lo g_{3} (x) = 1

Add

lo g_{3} (x)

to both sides

lo g_{3} (8 x + 1) - lo g_{3} (x) + lo g_{3} (x) = 1 + lo g_{3} (x)

Simplify

lo g_{3} (8 x + 1) = 1 + lo g_{3} (x)

Apply log rules

8 x + 1 = 3 x

Solve

8 x + 1 = 3 x : x = - \frac{1}{5}

x = - \frac{1}{5}

Verify Solutions:

x = - \frac{1}{5}

False

The solution is

No Solution for x \in R

0.3 = ln (x)

ln (x) - 3 = ln (\frac{1}{x})

x, lo g_{4} (8 x + 3) = 1

2 ln (x) - ln (x^{2} + x - 3) = ln (1)

ln (x) = 5.827

What is the answer to log_{3}(8x+1)-log_{3}(x)=1 ?
The answer to log_{3}(8x+1)-log_{3}(x)=1 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(8x+1)-log_{3}(x)=1
The solution is No Solution for x\in\mathbb{R}