What is the answer to log_{2}(x)=-0.8 ?

The answer to log_{2}(x)=-0.8 is x= 1/(2^{0.8)}

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log_{2}(x)=-0.8

lo g_{2} (x) = - 0.8

x = \frac{1}{2 ^{0.8}}

Decimal Notation

x = 0.57434 \dots

Solution steps

lo g_{2} (x) = - 0.8

Apply log rules

x = \frac{1}{2 ^{0.8}}

lo g_{2} (x) = - 0.5

lo g_{2} (x) = - 0.7

lo g_{10} (3) + lo g_{10} (x) = 2

3.3 = - lo g_{10} (c)

lo g_{2} (x + 3) + lo g_{2} (x + 6) = 2

What is the answer to log_{2}(x)=-0.8 ?
The answer to log_{2}(x)=-0.8 is x= 1/(2^{0.8)}
Solve for x: log_{2}(x)=-0.8
The solution is x= 1/(2^{0.8)}