What is the answer to log_{2}(x+3)+log_{2}(x+6)=2 ?

The answer to log_{2}(x+3)+log_{2}(x+6)=2 is x=-2

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log_{2}(x+3)+log_{2}(x+6)=2

lo g_{2} (x + 3) + lo g_{2} (x + 6) = 2

x = - 2

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x + 6) = 2

Apply log rules

(x + 3) (x + 6) = 4

Solve

(x + 3) (x + 6) = 4 : x = - 2, x = - 7

x = - 2, x = - 7

Verify Solutions:

x = - 2

True

, x = - 7

False

The solution is

x = - 2

ln (9 x) + 5 = ln (3 x + 4)

2 x + 2 \cdot ln (x + 1) + D = 2

lo g_{3} (x + 1) - lo g_{3} (x) = 3

lo g_{6} (x + 1) + lo g_{6} (x) = 1

lo g_{2} (x) = (lo g_{2} (x))^{2}

What is the answer to log_{2}(x+3)+log_{2}(x+6)=2 ?
The answer to log_{2}(x+3)+log_{2}(x+6)=2 is x=-2
Solve for x: log_{2}(x+3)+log_{2}(x+6)=2
The solution is x=-2