What is the answer to ln(x+7)+ln(x-4)=2ln(x) ?

The answer to ln(x+7)+ln(x-4)=2ln(x) is x= 28/3

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ln(x+7)+ln(x-4)=2ln(x)

ln (x + 7) + ln (x - 4) = 2 ln (x)

x = \frac{28}{3}

Decimal Notation

x = 9.33333 \dots

Solution steps

ln (x + 7) + ln (x - 4) = 2 ln (x)

Apply log rules

(x + 7) (x - 4) = x^{2}

Solve

(x + 7) (x - 4) = x^{2} : x = \frac{28}{3}

x = \frac{28}{3}

Verify Solutions:

x = \frac{28}{3}

True

The solution is

x = \frac{28}{3}

lo g_{10} (x) = 0.00002

lo g_{5} (x) = 3 - lo g_{5} (x + 20)

2 - 2.12 = lo g_{10} (x)

- 35.5 = 10 lo g_{10} (\frac{x}{1})

lo g_{10} (2 + x) = 1

What is the answer to ln(x+7)+ln(x-4)=2ln(x) ?
The answer to ln(x+7)+ln(x-4)=2ln(x) is x= 28/3
Solve for x: ln(x+7)+ln(x-4)=2ln(x)
The solution is x= 28/3