What is the answer to log_{2}((r+8)^2)=4 ?

The answer to log_{2}((r+8)^2)=4 is r=-4,r=-12

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log_{2}((r+8)^2)=4

lo g_{2} ((r + 8)^{2}) = 4

r = - 4, r = - 12

Solution steps

lo g_{2} ((r + 8)^{2}) = 4

Apply log rules

(r + 8)^{2} = 16

Solve

(r + 8)^{2} = 16 : r = - 4, r = - 12

r = - 4, r = - 12

8 lo g_{10} (n) - n = 0

ln (x - 10) = ln (8)

lo g_{x} (100) = 140

lo g_{- 2 x - 8} (2 x^{2} + 6 x - 20) = 2

v, ln (v) = - 2 t + ln (20)

What is the answer to log_{2}((r+8)^2)=4 ?
The answer to log_{2}((r+8)^2)=4 is r=-4,r=-12
Solve for r: log_{2}((r+8)^2)=4
The solution is r=-4,r=-12