What is the answer to solvefor v,ln(v)=-2t+ln(20) ?

The answer to solvefor v,ln(v)=-2t+ln(20) is v=20e^{-2t}

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solvefor v,ln(v)=-2t+ln(20)

solve for

v, ln (v) = - 2 t + ln (20)

v = 20 e^{- 2 t}

Solution steps

ln (v) = - 2 t + ln (20)

Apply log rules

v = 20 e^{- 2 t}

lo g_{2 x - 5} (2 x^{2} - 2 x - 15) = 2

lo g_{12} (1 + \frac{r}{100}) = 3

lo g_{5} (x) - lo g_{5} (x - 1) = 1

lo g_{6} (x + 4) = 1 - lo g_{6} (x + 3)

lo g_{4} (x) = lo g_{x} (16)

What is the answer to solvefor v,ln(v)=-2t+ln(20) ?
The answer to solvefor v,ln(v)=-2t+ln(20) is v=20e^{-2t}