What is the answer to log_{2x}(16)=-2 ?

The answer to log_{2x}(16)=-2 is x= 1/8

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log_{2x}(16)=-2

lo g_{2 x} (16) = - 2

x = \frac{1}{8}

Decimal Notation

x = 0.125

Solution steps

lo g_{2 x} (16) = - 2

Apply log rules

\frac{1}{lo g _{16} ( 2 x )} = - 2

Multiply both sides by

lo g_{16} (2 x)

\frac{1}{lo g _{16} ( 2 x )} lo g_{16} (2 x) = - 2 lo g_{16} (2 x)

Apply log rules

x = \frac{1}{8}

Verify Solutions:

x = \frac{1}{8}

True

The solution is

x = \frac{1}{8}

lo g_{2} (x^{2} - 1) - 2 = 0

lo g_{10} (E) = (11.8 + 1.5 (8))

lo g_{x + 7} (3 x) = 2

lo g_{10} (2 x) - lo g_{10} (x - 4) = 1

ln (x) = 0.24