What is the answer to ln(3)+ln(x-1)=-1 ?

The answer to ln(3)+ln(x-1)=-1 is x= 1/(3e)+1

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ln(3)+ln(x-1)=-1

ln (3) + ln (x - 1) = - 1

x = \frac{1}{3 e} + 1

Decimal Notation

x = 1.12262 \dots

Solution steps

ln (3) + ln (x - 1) = - 1

Move

ln (3)

to the right side

ln (x - 1) = - 1 - ln (3)

Apply log rules

x - 1 = \frac{1}{3 e}

Solve

x - 1 = \frac{1}{3 e} : x = \frac{1}{3 e} + 1

x = \frac{1}{3 e} + 1

Verify Solutions:

x = \frac{1}{3 e} + 1

True

The solution is

x = \frac{1}{3 e} + 1

lo g_{a} (\frac{4}{9}) = 2

lo g_{2} (x^{3} - 4) = 2

\frac{2 lo g _{2} ( x ) - 3}{3} = 1

lo g_{4} (x^{3} - 3 x) = 1

lo g_{4} (2 x) + lo g_{4} (x - 2) = 2

What is the answer to ln(3)+ln(x-1)=-1 ?
The answer to ln(3)+ln(x-1)=-1 is x= 1/(3e)+1
Solve for x: ln(3)+ln(x-1)=-1
The solution is x= 1/(3e)+1