What is the answer to log_{2}(log_{2}(x))-1=1 ?

The answer to log_{2}(log_{2}(x))-1=1 is x=16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(log_{2}(x))-1=1

lo g_{2} (lo g_{2} (x)) - 1 = 1

x = 16

Solution steps

lo g_{2} (lo g_{2} (x)) - 1 = 1

Move

1

to the right side

lo g_{2} (lo g_{2} (x)) = 2

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

b, a = lo g_{10} (b)

y, ln (y) = ln (m) - k t

ln (x) \cdot (- 185) = 600

lo g_{5} (2 x - 1) + lo g_{25} (9) = 2

20 lo g_{10} (x) = - 20

What is the answer to log_{2}(log_{2}(x))-1=1 ?
The answer to log_{2}(log_{2}(x))-1=1 is x=16
Solve for x: log_{2}(log_{2}(x))-1=1
The solution is x=16