What is the answer to log_{5}(2x-1)+log_{25}(9)=2 ?

The answer to log_{5}(2x-1)+log_{25}(9)=2 is x= 14/3

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log_{5}(2x-1)+log_{25}(9)=2

lo g_{5} (2 x - 1) + lo g_{25} (9) = 2

x = \frac{14}{3}

Decimal Notation

x = 4.66666 \dots

Solution steps

lo g_{5} (2 x - 1) + lo g_{25} (9) = 2

Move

lo g_{25} (9)

to the right side

lo g_{5} (2 x - 1) = 2 - lo g_{25} (9)

Apply log rules

2 x - 1 = \frac{25}{3}

Solve

2 x - 1 = \frac{25}{3} : x = \frac{14}{3}

x = \frac{14}{3}

Verify Solutions:

x = \frac{14}{3}

True

The solution is

x = \frac{14}{3}

20 lo g_{10} (x) = - 20

lo g_{10} (b) = 1.8

lo g_{3} (X) = 5

lo g_{3} (X) = 2

lo g_{2} (7 x + 5) = 5

What is the answer to log_{5}(2x-1)+log_{25}(9)=2 ?
The answer to log_{5}(2x-1)+log_{25}(9)=2 is x= 14/3
Solve for x: log_{5}(2x-1)+log_{25}(9)=2
The solution is x= 14/3