What is the answer to log_{2}(7x+5)=5 ?

The answer to log_{2}(7x+5)=5 is x= 27/7

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log_{2}(7x+5)=5

lo g_{2} (7 x + 5) = 5

x = \frac{27}{7}

Decimal Notation

x = 3.85714 \dots

Solution steps

lo g_{2} (7 x + 5) = 5

Apply log rules

7 x + 5 = 32

Solve

7 x + 5 = 32 : x = \frac{27}{7}

x = \frac{27}{7}

lo g_{x} (6 + x) = 2

ln (x) + x - 1 = 0

lo g_{9} (x + 3) = 1 + lo g_{9} (x - 2)

4 = \frac{n}{lo g _{10} ( n )}

t, ln (t) mb = ln (70) + 0.75 ln (m)

What is the answer to log_{2}(7x+5)=5 ?
The answer to log_{2}(7x+5)=5 is x= 27/7
Solve for x: log_{2}(7x+5)=5
The solution is x= 27/7