What is the answer to ln(x)+ln(2x)+ln(4x)=3 ?

The answer to ln(x)+ln(2x)+ln(4x)=3 is x=e^{(3-3ln(2))/3}

Solve for x: ln(x)+ln(2x)+ln(4x)=3

The solution is x=e^{(3-3ln(2))/3}

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ln (x) + ln (2 x) + ln (4 x) = 3

x = e^{\frac{3 - 3 l n ( 2 )}{3}}

Decimal Notation

x = 1.35914 \dots

Solution steps

ln (x) + ln (2 x) + ln (4 x) = 3

Apply log rules

x = e^{\frac{3 - 3 l n ( 2 )}{3}}

Verify Solutions:

x = e^{\frac{3 - 3 l n ( 2 )}{3}}

True

The solution is

x = e^{\frac{3 - 3 l n ( 2 )}{3}}

ln (x) + ln (x - 6) = 2

ln (x) + ln (x - 6) = 3

ln (20 x - 13) - 13 ln (1) = 0

2 ln (x) - ln (3) = 2

lo g_{10} (x) - lo g_{10} (x - 6) = 4

What is the answer to ln(x)+ln(2x)+ln(4x)=3 ?
The answer to ln(x)+ln(2x)+ln(4x)=3 is x=e^{(3-3ln(2))/3}
Solve for x: ln(x)+ln(2x)+ln(4x)=3
The solution is x=e^{(3-3ln(2))/3}