What is the answer to -6+log_{10}(6v)=-7 ?

The answer to -6+log_{10}(6v)=-7 is v= 1/60

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-6+log_{10}(6v)=-7

- 6 + lo g_{10} (6 v) = - 7

v = \frac{1}{60}

Decimal Notation

v = 0.01666 \dots

Solution steps

- 6 + lo g_{10} (6 v) = - 7

Move

6

to the right side

lo g_{10} (6 v) = - 1

Apply log rules

6 v = \frac{1}{10}

Solve

6 v = \frac{1}{10} : v = \frac{1}{60}

v = \frac{1}{60}

Verify Solutions:

v = \frac{1}{60}

True

The solution is

v = \frac{1}{60}

4.35 = 3 - lo g_{10} (x)

lo g_{3} (x) = lo g_{9} (3 x - 2)

lo g_{a} (49) = \frac{2}{3}

lo g_{x - 3} (2 x^{2} - 11 x + 16) = 2

lo g_{10} (x) (343) = 3

What is the answer to -6+log_{10}(6v)=-7 ?
The answer to -6+log_{10}(6v)=-7 is v= 1/60
Solve for v: -6+log_{10}(6v)=-7
The solution is v= 1/60