What are the solutions to the equation 3x^2+11x-20=0 ?

The solutions to the equation 3x^2+11x-20=0 are x= 4/3 ,x=-5

Find the zeros of 3x^2+11x-20=0

The zeros of 3x^2+11x-20=0 are x= 4/3 ,x=-5

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3 x^{2} + 11 x - 20 = 0

x = \frac{4}{3}, x = - 5

Solution steps

3 x^{2} + 11 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 20) = 19

x_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 19}{2 \cdot 3}, x_{2} = \frac{- 11 - 19}{2 \cdot 3}

x = \frac{- 11 + 19}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 11 - 19}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 5

5 ∣ x - 1 ∣ - 4 > 31

12 + \frac{x}{5} = 12

- 8 (2 x + 8) \geq - 4 (4 x + 2)

49 x^{2} + 36 = 0

\frac{x - 6}{x + 5} \leq 0

What are the solutions to the equation 3x^2+11x-20=0 ?
The solutions to the equation 3x^2+11x-20=0 are x= 4/3 ,x=-5
Find the zeros of 3x^2+11x-20=0
The zeros of 3x^2+11x-20=0 are x= 4/3 ,x=-5