What are the solutions to the equation 49x^2+36=0 ?

The solutions to the equation 49x^2+36=0 are x= 6/7 i,x=-6/7 i

Find the zeros of 49x^2+36=0

The zeros of 49x^2+36=0 are x= 6/7 i,x=-6/7 i

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49 x^{2} + 36 = 0

x = \frac{6}{7} i, x = - \frac{6}{7} i

Solution steps

49 x^{2} + 36 = 0

Move

36

to the right side

49 x^{2} = - 36

Divide both sides by

49

x^{2} = - \frac{36}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{36}{49}, x = - - \frac{36}{49}

- \frac{36}{49} = \frac{6}{7} i

- - \frac{36}{49} = - \frac{6}{7} i

x = \frac{6}{7} i, x = - \frac{6}{7} i

\frac{x - 6}{x + 5} \leq 0

7 y = 33 - 4 y

\frac{1}{6} - \frac{1}{4}

\frac{1}{3 + 2}

(x + 1)^{3} - (x - 1)^{3} = 6 x (x - 3)

What are the solutions to the equation 49x^2+36=0 ?
The solutions to the equation 49x^2+36=0 are x= 6/7 i,x=-6/7 i
Find the zeros of 49x^2+36=0
The zeros of 49x^2+36=0 are x= 6/7 i,x=-6/7 i