What is the answer to (x+1)^3-(x-1)^3=6x(x-3) ?

The answer to (x+1)^3-(x-1)^3=6x(x-3) is x=-1/9

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(x+1)^3-(x-1)^3=6x(x-3)

(x + 1)^{3} - (x - 1)^{3} = 6 x (x - 3)

x = - \frac{1}{9}

Solution steps

(x + 1)^{3} - (x - 1)^{3} = 6 x (x - 3)

Expand

(x + 1)^{3} - (x - 1)^{3} : 6 x^{2} + 2

Expand

6 x (x - 3) : 6 x^{2} - 18 x

6 x^{2} + 2 = 6 x^{2} - 18 x

Move

2

to the right side

6 x^{2} = 6 x^{2} - 18 x - 2

Subtract

6 x^{2} - 18 x

from both sides

6 x^{2} - (6 x^{2} - 18 x) = 6 x^{2} - 18 x - 2 - (6 x^{2} - 18 x)

Simplify

18 x = - 2

Divide both sides by

18

x = - \frac{1}{9}

x - 1 = 4

\frac{y}{- 3} = 33

(1 + 6 s)^{2} = 1 + 30 s

4 x + 6 = 4 (6 x - 3) + 58

- 63 < - 9 c

What is the answer to (x+1)^3-(x-1)^3=6x(x-3) ?
The answer to (x+1)^3-(x-1)^3=6x(x-3) is x=-1/9
Solve for x: (x+1)^3-(x-1)^3=6x(x-3)
The solution is x=-1/9