What is the answer to log_{2}(x+5)+log_{2}(4x+4)=7 ?

The answer to log_{2}(x+5)+log_{2}(4x+4)=7 is x=3

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log_{2}(x+5)+log_{2}(4x+4)=7

lo g_{2} (x + 5) + lo g_{2} (4 x + 4) = 7

x = 3

Solution steps

lo g_{2} (x + 5) + lo g_{2} (4 x + 4) = 7

Apply log rules

(x + 5) (4 x + 4) = 128

Solve

(x + 5) (4 x + 4) = 128 : x = 3, x = - 9

x = 3, x = - 9

Verify Solutions:

x = 3

True

, x = - 9

False

The solution is

x = 3

x^{(2 l o g_{9} (x)) - 1} = 3 x

lo g_{2} (x^{2} + 2 x - 2) = 0

lo g_{4} (2 x + 6) = 2

0.57 = ln (y)

- ln (x + 1) = 1

What is the answer to log_{2}(x+5)+log_{2}(4x+4)=7 ?
The answer to log_{2}(x+5)+log_{2}(4x+4)=7 is x=3
Solve for x: log_{2}(x+5)+log_{2}(4x+4)=7
The solution is x=3