What is the answer to log_{2}(x-2)+log_{2}(x-4)=3 ?

The answer to log_{2}(x-2)+log_{2}(x-4)=3 is x=6

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log_{2}(x-2)+log_{2}(x-4)=3

lo g_{2} (x - 2) + lo g_{2} (x - 4) = 3

x = 6

Solution steps

lo g_{2} (x - 2) + lo g_{2} (x - 4) = 3

Apply log rules

(x - 2) (x - 4) = 8

Solve

(x - 2) (x - 4) = 8 : x = 6, x = 0

x = 6, x = 0

Verify Solutions:

x = 6

True

, x = 0

False

The solution is

x = 6

lo g_{y} (2) - lo g_{4} (y) = 1

lo g_{4} (1 + x^{2}) = - 0.25

lo g_{10} (y) = - 138.265

lo g_{2} (\frac{1}{x}) = - 1

ln (x - 2) - ln (8) = 2

What is the answer to log_{2}(x-2)+log_{2}(x-4)=3 ?
The answer to log_{2}(x-2)+log_{2}(x-4)=3 is x=6
Solve for x: log_{2}(x-2)+log_{2}(x-4)=3
The solution is x=6