What is the answer to (log_{3}(x))^2=4 ?

The answer to (log_{3}(x))^2=4 is x=9,x= 1/9

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(log_{3}(x))^2=4

(lo g_{3} (x))^{2} = 4

x = 9, x = \frac{1}{9}

Decimal Notation

x = 9, x = 0.11111 \dots

Solution steps

(lo g_{3} (x))^{2} = 4

Rewrite the equation with

lo g_{3} (x) = u

(u)^{2} = 4

Solve

u^{2} = 4 : u = 4, u = - 4

u = 4, u = - 4

Substitute back

u = lo g_{3} (x),

solve for

x

Solve

lo g_{3} (x) = 4 : x = 9

Solve

lo g_{3} (x) = - 4 : x = \frac{1}{9}

x = 9, x = \frac{1}{9}

Verify Solutions:

x = 9

True

, x = \frac{1}{9}

True

The solutions are

x = 9, x = \frac{1}{9}

ln (x - 5) - ln (x - 2) = ln (2)

ln (x) - ln (x) = 0

- 0.625 = ln (x)

37.9 = lo g_{10} (r^{20})

ln (4) + ln (x - 3) = - 2

What is the answer to (log_{3}(x))^2=4 ?
The answer to (log_{3}(x))^2=4 is x=9,x= 1/9
Solve for x: (log_{3}(x))^2=4
The solution is x=9,x= 1/9