What is the answer to log_{4}(4x^2)-log_{4}(9)=3 ?

The answer to log_{4}(4x^2)-log_{4}(9)=3 is x=12,x=-12

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log_{4}(4x^2)-log_{4}(9)=3

lo g_{4} (4 x^{2}) - lo g_{4} (9) = 3

x = 12, x = - 12

Solution steps

lo g_{4} (4 x^{2}) - lo g_{4} (9) = 3

Move

lo g_{4} (9)

to the right side

lo g_{4} (4 x^{2}) = 3 + lo g_{4} (9)

Apply log rules

4 x^{2} = 576

Solve

4 x^{2} = 576 : x = 12, x = - 12

x = 12, x = - 12

Verify Solutions:

x = 12

True

, x = - 12

True

The solutions are

x = 12, x = - 12

lo g_{\frac{1}{2}} (x) = 99500

lo g_{6} (x^{6}) = 1

5 lo g_{10} (x - 13) = 1

lo g_{10} (lo g_{10} (x)) = 1.01

lo g_{10} (x) = 17

What is the answer to log_{4}(4x^2)-log_{4}(9)=3 ?
The answer to log_{4}(4x^2)-log_{4}(9)=3 is x=12,x=-12
Solve for x: log_{4}(4x^2)-log_{4}(9)=3
The solution is x=12,x=-12