What is the answer to (log_{3}((2x+2)^3))^2=36 ?

The answer to (log_{3}((2x+2)^3))^2=36 is x= 7/2 ,x=-17/18

Solve for x: (log_{3}((2x+2)^3))^2=36

The solution is x= 7/2 ,x=-17/18

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(lo g_{3} ((2 x + 2)^{3}))^{2} = 36

x = \frac{7}{2}, x = - \frac{17}{18}

Decimal Notation

x = 3.5, x = - 0.94444 \dots

Solution steps

(lo g_{3} ((2 x + 2)^{3}))^{2} = 36

Rewrite the equation with

lo g_{3} ((2 x + 2)^{3}) = u

(u)^{2} = 36

Solve

u^{2} = 36 : u = 36, u = - 36

u = 36, u = - 36

Substitute back

u = lo g_{3} ((2 x + 2)^{3}),

solve for

x

Solve

lo g_{3} ((2 x + 2)^{3}) = 36 : x = \frac{7}{2}

Solve

lo g_{3} ((2 x + 2)^{3}) = - 36 : x = - \frac{17}{18}

x = \frac{7}{2}, x = - \frac{17}{18}

Verify Solutions:

x = \frac{7}{2}

True

, x = - \frac{17}{18}

True

The solutions are

x = \frac{7}{2}, x = - \frac{17}{18}

lo g_{2} (9) + lo g_{2} (x + 3) = 3

lo g_{10} (c) = 0.5

x, ln (y) = - 2 ln (x) + c

12 = - 10 lo g_{10} ((1 - x)^{2})

ln (γ) = ln (4 + e^{2^{β}}) + ω

What is the answer to (log_{3}((2x+2)^3))^2=36 ?
The answer to (log_{3}((2x+2)^3))^2=36 is x= 7/2 ,x=-17/18
Solve for x: (log_{3}((2x+2)^3))^2=36
The solution is x= 7/2 ,x=-17/18