What is the answer to log_{10}(x+5)+log_{10}(2x)=2 ?

The answer to log_{10}(x+5)+log_{10}(2x)=2 is x=5

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log_{10}(x+5)+log_{10}(2x)=2

lo g_{10} (x + 5) + lo g_{10} (2 x) = 2

x = 5

Solution steps

lo g_{10} (x + 5) + lo g_{10} (2 x) = 2

Apply log rules

(x + 5) \cdot 2 x = 100

Solve

(x + 5) \cdot 2 x = 100 : x = 5, x = - 10

x = 5, x = - 10

Verify Solutions:

x = 5

True

, x = - 10

False

The solution is

x = 5

2 lo g_{x} (125) = 6

lo g_{3} (x^{2} + x) = lo g_{3} (4 x)

7 = 11.2 + lo g_{10} (x)

lo g_{3} (x^{3}) = lo g_{9} (27)

ln (x) = 9.976242681

What is the answer to log_{10}(x+5)+log_{10}(2x)=2 ?
The answer to log_{10}(x+5)+log_{10}(2x)=2 is x=5
Solve for x: log_{10}(x+5)+log_{10}(2x)=2
The solution is x=5