What is the answer to log_{3}(x^2+x)=log_{3}(4x) ?

The answer to log_{3}(x^2+x)=log_{3}(4x) is x=3

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log_{3}(x^2+x)=log_{3}(4x)

lo g_{3} (x^{2} + x) = lo g_{3} (4 x)

x = 3

Solution steps

lo g_{3} (x^{2} + x) = lo g_{3} (4 x)

Apply log rules

x^{2} + x = 4 x

Solve

x^{2} + x = 4 x : x = 3, x = 0

x = 3, x = 0

Verify Solutions:

x = 3

True

, x = 0

False

The solution is

x = 3

7 = 11.2 + lo g_{10} (x)

lo g_{3} (x^{3}) = lo g_{9} (27)

ln (x) = 9.976242681

1.02 = lo g_{10} (x)

6 lo g_{3} (x - 3) = - 24

What is the answer to log_{3}(x^2+x)=log_{3}(4x) ?
The answer to log_{3}(x^2+x)=log_{3}(4x) is x=3
Solve for x: log_{3}(x^2+x)=log_{3}(4x)
The solution is x=3