What are the solutions to the equation w^2=32w ?

The solutions to the equation w^2=32w are w=32,w=0

Find the zeros of w^2=32w

The zeros of w^2=32w are w=32,w=0

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w^{2} = 32 w

w = 32, w = 0

Solution steps

w^{2} = 32 w

Move

32 w

to the left side

w^{2} - 32 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 32)^{2} - 4 \cdot 1 \cdot 0 = 32

w_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 1}, w_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 1}

w = \frac{- ( - 32 ) + 32}{2 \cdot 1} : 32

w = \frac{- ( - 32 ) - 32}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

w = 32, w = 0

- 4 x^{2} + x^{2} + 147 = 0

- 4 < 5 - 3 x \leq 17

\frac{8}{3} \cdot 2

x^{2} - 120 x - 3600 = 0

\frac{( - \frac{15}{17} )}{( - \frac{8}{17} )}

What are the solutions to the equation w^2=32w ?
The solutions to the equation w^2=32w are w=32,w=0
Find the zeros of w^2=32w
The zeros of w^2=32w are w=32,w=0